[BOJ][10950] A+B - 3
Updated:
1. 문제 링크
https://www.acmicpc.net/problem/10950
2. 사용 알고리즘
구현
3. 풀이
두 개의 정수를 입력받아 덧셈 결과 출력
4. 소스 코드
4-1. C++
https://github.com/dev-aiden/problem-solving/blob/main/boj/10950.cpp
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#include <iostream>
using namespace std;
int main(void) {
ios_base::sync_with_stdio(false);
int t; for (cin >> t; t--;) {
int a, b; cin >> a >> b;
cout << a + b << '\n';
}
return 0;
}
4-2. JAVA
https://github.com/dev-aiden/problem-solving/blob/main/boj/10950.java
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import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class Main {
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringBuilder sb = new StringBuilder();
int t = Integer.parseInt(br.readLine());
for(int i = 0; i < t; ++i) {
StringTokenizer st = new StringTokenizer(br.readLine(), " ");
sb.append(Integer.parseInt(st.nextToken()) + Integer.parseInt(st.nextToken())).append('\n');
}
System.out.println(sb);
br.close();
}
}
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